The pressure drop, that you see in the fan diagram, are only for the fan with an inlet air density of 1,2 kg/m3 (110 Pa), while in the calculation , it is necessary to consider an air density higher because the air pass through the coil (in fact the fan is after the coil-sucking position): it is about 1,46 kg/m3. Then it is necessary to divide 1,46/1,2= 1,216. This value (1,216) have to be multiply for 110 Pa= 134 Pa, so you obtain the air side pressure drop.
In the attachment, you can see the balance between the fan and the coil:
